q-2-7q-28=q^2+2q-8

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Solution for q-2-7q-28=q^2+2q-8 equation: 



q-2-7q-28=q^2+2q-8

We move all terms to the left:

q-2-7q-28-(q^2+2q-8)=0

We add all the numbers together, and all the variables

-6q-(q^2+2q-8)-30=0

We get rid of parentheses

-q^2-6q-2q+8-30=0

We add all the numbers together, and all the variables

-1q^2-8q-22=0

a = -1; b = -8; c = -22;
Δ = b2-4ac
Δ = -82-4·(-1)·(-22)
Δ = -24
Delta is less than zero, so there is no solution for the equation

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